# P6 PSLE Maths (Area)

May 1, 2018

In the figure above, Rectangles ACLN and FGHI are the same. Squares CDEF and IJKL are the same. AC= 2CL. B and M are midpoints for AC and LN, respectively. O is the midpoint of ABMN. Perimeter of CFIL = 12cm. Total area of ACLN, FGHI, IJKL and CDEF =  72 square cm.Express the area of CBOL as a fraction of the whole figure.

➡️NOL= 0.25 ACLN
➡️ABN= 0.25 ACLN

➡️CBOL=1-0.25-0.25=0.5 of ACLN

➡️ACLN+CDEF= 36 square cm

➡️CF+CL= 12➗2=6

➡️
Try CF= 1
Hence CL=5
AC=10

Area of ACLN=AC x CL=10 x 5=50

Area of CDEF= 1

Total area of ACLN + CDEF= 51 square cm (rejected)

➡️
Try CF=2
Hence CL= 4
AC= 8

Area of ACLN=AC x CL=4x 8= 32

Area of CDEF= 2x2 =4

Total area of ACLN + CDEF= 36 square cm

➡️Hence
CL=4
AC=8
CF=2

➡️Total area of figure= 2(4x8) + 2x4 + 2(2x2)= 80 square cm

➡️Area of CBOL= 0.5 of ACLN = 0.5 x 8x 4= 16 square cm

➡️Fraction of CBOL of the whole figure= 16/80= 9/40

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